This weather station measures 947 watts/m² incident solar energy.
I have four Fresnel lenses which sum up to 3991 in² which is 2.57 m² and with the figure 947 Watts/m² this becomes 138 BTU/minute.
A solar tracking device is in the planning and material collection stage of research involving solar tracking circuitry, motors controlled by it to control the Fresnel lenses so they track the sun focusing the sun's rays on the Aluminum pipe.
I have a 2.5 gallon water heater which is rated at 1440 Watts which converts to 81 BTU/min.
In addition I have an inline water heater element fixture which allows a heater blade of 1500 Watts which is 85 BTU/min. This totals to 304 BTU/min.
The centrifuge needs 55 gph flow rate and 180°F. I have an Aluminum pipe(1) 3" ID 10 feet long. It is threaded on both ends and has couplings and bushings and insulating couplings to fit 3/4 NPT Stainless steel.
I examined a years worth of solar incident radiation and the value of 947 w/m² seems a bit high. I need to do more research to get better figures. To compensate I bought a 3500W heating element which requires 240V and is valued at 199 BTU/min -=- The calculations below are amended to upgrade as the granularity of the process is tuned to a finer degree.

100 BTU/min discounted boiler contribution
81 BTU/min 2.5 gal water heater
85 BTU/min first inline heater
199 BTU/min second inline heater if I buy another special plumbing T
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465 BTU/min x 4 min x 25.7 pounds WVO/ .4 BTU/#WVO x delta T(°F)
solving for delta T gives 180 °F so with this setup I can start with oil at 0 °F

Dark day?
365 BTU/min x 4 min x 25.7 pounds WVO/ .4 BTU/#WVO x delta T(°F)
solving for delta T gives 142 °F so with this setup I can start with oil at 18 °F

Can I drop also the 2.5 gal H₂O heater?
284 BTU/min x 4 min x 25.7 pounds WVO/ .4 BTU/#WVO x delta T(°F)
solving for delta T gives 110 °F so with this setup I can start with oil at 50 °F

swap out the 1500W heater element and insert the 3500W element:

100 BTU/min discounted boiler contribution
81 BTU/min 2.5 gal hater heater
199 BTU/min first inline heater swapped elements
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380 BTU/min x 4 min x 25.7 pounds WVO/ .4 BTU/#WVO x delta T(°F)
solving for delta T gives 148 °F
The documentation for the centrifuge states that 160°F is adequate so I can start with oil that is 12°F

Can I do this on a dark day?
280 BTU/min x 4 min x 25.7 pounds/.4 BTU/#-°F gives 109°F so the oil has to be 51°F to start if there is no sunlight to capture the oil is going to be colder than 51 so the next calcuulation has two inline heating elements


361 BTU/min x 4 x 25.7/.4 equals 140°F so the oil has to start at 20°

=-=-=-=-=-=-=-=-=-= calculations based on 947 W/m² =-=-=-=-=-=-=-=-=-=
With a way to track the sun I can keep the pipe in the focus of the Fresnel lenses transferring this 138 BTU/min to the waste vegetable oil(WVO) in the pipe. Its volume is 3.67 gallons. 55 gph and 3.67 gallons becomes one pipe volume change every 4 minutes. I have a carbonator pump which has a flow rate of 85 gph at 120 psi. With 304 BTU/min from the solar lenses and the resident time of 4 minutes and the heater blades is 1216 BTU's. WVO is 7 pounds/gallon so the pipe has 25.7 pounds WVO The specific heat of WVO is .4 BTU/pound-°F so with 25.7 pounds and 1216 BTU's this becomes 118 °F temperature change and we want 180 °F so if the WVO is 68°F or higher then these three sources of heat will be adequate for the job and the thermostat in the 2.5 gal water heater will suffice. The purpose of the centrifuge is to remove particles in the WVO prior to its conversion to biodiesel
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